Variant Calling Workflow

Overview

Teaching: 35 min
Exercises: 25 min
Questions
  • How do I find sequence variants between my sample and a reference genome?

Objectives
  • Understand the steps involved in variant calling.

  • Describe the types of data formats encountered during variant calling.

  • Use command line tools to perform variant calling.

We mentioned before that we are working with files from a long-term evolution study of an E. coli population (designated Ara-3). Now that we have looked at our data to make sure that it is high quality, and removed low-quality base calls, we can perform variant calling to see how the population changed over time. We care how this population changed relative to the original population, E. coli strain REL606. Therefore, we will align each of our samples to the E. coli REL606 reference genome, and see what differences exist in our reads versus the genome.

Alignment to a reference genome

workflow_align

We perform read alignment or mapping to determine where in the genome our reads originated from. There are a number of tools to choose from and, while there is no gold standard, there are some tools that are better suited for particular NGS analyses. We will be using the Burrows Wheeler Aligner (BWA), which is a software package for mapping low-divergent sequences against a large reference genome.

The alignment process consists of two steps:

  1. Indexing the reference genome
  2. Aligning the reads to the reference genome

Setting up

First we download the reference genome for E. coli REL606. Although we could copy or move the file with cp or mv, most genomics workflows begin with a download step, so we will practice that here.

$ cd ~/cs_course
$ curl -L -o data/ecoli_rel606.fasta.gz ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/000/017/985/GCA_000017985.1_ASM1798v1/GCA_000017985.1_ASM1798v1_genomic.fna.gz
$ gunzip data/ecoli_rel606.fasta.gz

Exercise

We saved this file as data/ecoli_rel606.fasta.gz and then decompressed it. What is the real name of the genome?

Solution

$ head data/ecoli_rel606.fasta

The name of the sequence follows the > character. The name is CP000819.1 Escherichia coli B str. REL606, complete genome. Keep this chromosome name (CP000819.1) in mind, as we will use it later in the lesson.

We will also download a set of trimmed FASTQ files to work with. These are small subsets of our real trimmed data, and will enable us to run our variant calling workflow quite quickly.

$ curl -L -o sub.tar.gz https://ndownloader.figshare.com/files/14418248
$ tar xvf sub.tar.gz
$ mv sub/ ~/cs_course/data/trimmed_fastq_small

Index the reference genome

Our first step is to index the reference genome for use by BWA. Indexing allows the aligner to quickly find potential alignment sites for query sequences in a genome, which saves time during alignment. Indexing the reference only has to be run once. The only reason you would want to create a new index is if you are working with a different reference genome or you are using a different tool for alignment.

$ bwa index data/ecoli_rel606.fasta

While the index is created, you will see output that looks something like this:

[bwa_index] Pack FASTA... 0.04 sec
[bwa_index] Construct BWT for the packed sequence...
[bwa_index] 1.05 seconds elapse.
[bwa_index] Update BWT... 0.03 sec
[bwa_index] Pack forward-only FASTA... 0.02 sec
[bwa_index] Construct SA from BWT and Occ... 0.57 sec
[main] Version: 0.7.17-r1188
[main] CMD: bwa index data/ecoli_rel606.fasta
[main] Real time: 1.765 sec; CPU: 1.715 sec

Align reads to reference genome

The alignment process consists of choosing an appropriate reference genome to map our reads against and then deciding on an aligner. We will use the BWA-MEM algorithm, which is the latest and is generally recommended for high-quality queries as it is faster and more accurate.

An example of what a bwa command looks like is below. This command will not run, as we do not have the files ref_genome.fa, input_file_R1.fastq, or input_file_R2.fastq.

$ bwa mem ref_genome.fasta input_file_R1.fastq input_file_R2.fastq > output.sam

Have a look at the bwa options page. While we are running bwa with the default parameters here, your use case might require a change of parameters. NOTE: Always read the manual page for any tool before using and make sure the options you use are appropriate for your data.

We’re going to start by aligning the reads from just one of the samples in our dataset (SRR2584866). Later, we’ll be iterating this whole process on all of our sample files.

$ bwa mem data/ecoli_rel606.fasta data/trimmed_fastq_small/SRR2584866_1.trim.sub.fastq data/trimmed_fastq_small/SRR2584866_2.trim.sub.fastq > results/SRR2584866.aligned.sam

You will see output that starts like this:

[M::bwa_idx_load_from_disk] read 0 ALT contigs
[M::process] read 77446 sequences (10000033 bp)...
[M::process] read 77296 sequences (10000182 bp)...
[M::mem_pestat] # candidate unique pairs for (FF, FR, RF, RR): (48, 36728, 21, 61)
[M::mem_pestat] analysing insert size distribution for orientation FF...
[M::mem_pestat] (25, 50, 75) percentile: (420, 660, 1774)
[M::mem_pestat] low and high boundaries for computing mean and std.dev: (1, 4482)
[M::mem_pestat] mean and std.dev: (784.68, 700.87)
[M::mem_pestat] low and high boundaries for proper pairs: (1, 5836)
[M::mem_pestat] analysing insert size distribution for orientation FR...

SAM/BAM format

The SAM file, is a tab-delimited text file that contains information for each individual read and its alignment to the genome. While we do not have time to go into detail about the features of the SAM format, the paper by Heng Li et al. provides a lot more detail on the specification.

The compressed binary version of SAM is called a BAM file. We use this version to reduce size and to allow for indexing, which enables efficient random access of the data contained within the file.

The file begins with a header, which is optional. The header is used to describe the source of data, reference sequence, method of alignment, etc., this will change depending on the aligner being used. Following the header is the alignment section. Each line that follows corresponds to alignment information for a single read. Each alignment line has 11 mandatory fields for essential mapping information and a variable number of other fields for aligner specific information. An example entry from a SAM file is displayed below with the different fields highlighted.

sam_bam1

sam_bam2

We will convert the SAM file to BAM format using the samtools program with the view command and tell this command that the input is in SAM format (-S) and to output BAM format (-b). We will be doing the next few commands in the results folder, so we will change into that directory first:

$ cd results
$ samtools view -S -b SRR2584866.aligned.sam > SRR2584866.aligned.bam

Sort BAM file by coordinates

Next we sort the BAM file using the sort command from samtools. -o tells the command where to write the output.

$ samtools sort -o SRR2584866.aligned.sorted.bam SRR2584866.aligned.bam

Our files are pretty small, so we won’t see this output. If you run the workflow with larger files, you will see something like this:

[bam_sort_core] merging from 2 files...

SAM/BAM files can be sorted in multiple ways, e.g. by location of alignment on the chromosome, by read name, etc. It is important to be aware that different alignment tools will output differently sorted SAM/BAM, and different downstream tools require differently sorted alignment files as input.

You can use samtools to learn more about this bam file as well.

samtools flagstat SRR2584866.aligned.sorted.bam

This will give you the following statistics about your sorted bam file:

351169 + 0 in total (QC-passed reads + QC-failed reads)
0 + 0 secondary
1169 + 0 supplementary
0 + 0 duplicates
351103 + 0 mapped (99.98% : N/A)
350000 + 0 paired in sequencing
175000 + 0 read1
175000 + 0 read2
346688 + 0 properly paired (99.05% : N/A)
349876 + 0 with itself and mate mapped
58 + 0 singletons (0.02% : N/A)
0 + 0 with mate mapped to a different chr
0 + 0 with mate mapped to a different chr (mapQ>=5)

Variant calling

A variant call is a conclusion that there is a nucleotide difference vs. some reference at a given position in an individual genome or transcriptome, often referred to as a Single Nucleotide Polymorphism (SNP). The call is usually accompanied by an estimate of variant frequency and some measure of confidence. Similar to other steps in this workflow, there are a number of tools available for variant calling. In this workshop we will be using bcftools, but there are a few things we need to do before actually calling the variants.

workflow

Step 1: Calculate the read coverage of positions in the genome

Do the first pass on variant calling by counting read coverage with bcftools. We will use the command mpileup. The flag -O b tells bcftools to generate a bcf format output file, -o specifies where to write the output file, and -f flags the path to the reference genome:

$ bcftools mpileup -O b -o SRR2584866_raw.bcf \
-f ../data/ecoli_rel606.fasta SRR2584866.aligned.sorted.bam
[mpileup] 1 samples in 1 input files
[mpileup] maximum number of reads per input file set to -d 250

We have now generated a file with coverage information for every base.

Step 2: Detect the single nucleotide polymorphisms (SNPs)

Identify SNPs using bcftools call. We have to specify ploidy with the flag --ploidy, which is one for the haploid E. coli. -m allows for multiallelic and rare-variant calling, -v tells the program to output variant sites only (not every site in the genome), and -o specifies where to write the output file:

$ bcftools call --ploidy 1 -m -v -o SRR2584866_variants.vcf SRR2584866_raw.bcf

Step 3: Filter and report the SNP variants in variant calling format (VCF)

Filter the SNPs for the final output in VCF format, using vcfutils.pl:

$ vcfutils.pl varFilter SRR2584866_variants.vcf  > SRR2584866_final_variants.vcf

Explore the VCF format:

$ less -S SRR2584866_final_variants.vcf

You will see the header (which describes the format), the time and date the file was created, the version of bcftools that was used, the command line parameters used, and some additional information:

##fileformat=VCFv4.2
##FILTER=<ID=PASS,Description="All filters passed">
##bcftoolsVersion=1.8+htslib-1.8
##bcftoolsCommand=mpileup -O b -o SRR2584866_raw.bcf -f data/ecoli_rel606.fasta SRR2584866.aligned.sorted.bam
##reference=file://data/ecoli_rel606.fasta
##contig=<ID=CP000819.1,length=4629812>
##ALT=<ID=*,Description="Represents allele(s) other than observed.">
##INFO=<ID=INDEL,Number=0,Type=Flag,Description="Indicates that the variant is an INDEL.">
##INFO=<ID=IDV,Number=1,Type=Integer,Description="Maximum number of reads supporting an indel">
##INFO=<ID=IMF,Number=1,Type=Float,Description="Maximum fraction of reads supporting an indel">
##INFO=<ID=DP,Number=1,Type=Integer,Description="Raw read depth">
##INFO=<ID=VDB,Number=1,Type=Float,Description="Variant Distance Bias for filtering splice-site artefacts in RNA-seq data (bigger is better)",Version=
##INFO=<ID=RPB,Number=1,Type=Float,Description="Mann-Whitney U test of Read Position Bias (bigger is better)">
##INFO=<ID=MQB,Number=1,Type=Float,Description="Mann-Whitney U test of Mapping Quality Bias (bigger is better)">
##INFO=<ID=BQB,Number=1,Type=Float,Description="Mann-Whitney U test of Base Quality Bias (bigger is better)">
##INFO=<ID=MQSB,Number=1,Type=Float,Description="Mann-Whitney U test of Mapping Quality vs Strand Bias (bigger is better)">
##INFO=<ID=SGB,Number=1,Type=Float,Description="Segregation based metric.">
##INFO=<ID=MQ0F,Number=1,Type=Float,Description="Fraction of MQ0 reads (smaller is better)">
##FORMAT=<ID=PL,Number=G,Type=Integer,Description="List of Phred-scaled genotype likelihoods">
##FORMAT=<ID=GT,Number=1,Type=String,Description="Genotype">
##INFO=<ID=ICB,Number=1,Type=Float,Description="Inbreeding Coefficient Binomial test (bigger is better)">
##INFO=<ID=HOB,Number=1,Type=Float,Description="Bias in the number of HOMs number (smaller is better)">
##INFO=<ID=AC,Number=A,Type=Integer,Description="Allele count in genotypes for each ALT allele, in the same order as listed">
##INFO=<ID=AN,Number=1,Type=Integer,Description="Total number of alleles in called genotypes">
##INFO=<ID=DP4,Number=4,Type=Integer,Description="Number of high-quality ref-forward , ref-reverse, alt-forward and alt-reverse bases">
##INFO=<ID=MQ,Number=1,Type=Integer,Description="Average mapping quality">
##bcftools_callVersion=1.8+htslib-1.8
##bcftools_callCommand=call --ploidy 1 -m -v -o SRR2584866_variants.vcf SRR2584866_raw.bcf; Date=Tue Oct  9 18:48:10 2018

Followed by information on each of the variations observed:

#CHROM  POS     ID      REF     ALT     QUAL    FILTER  INFO    FORMAT  SRR2584866.aligned.sorted.bam
CP000819.1      1521    .       C       T       207     .       DP=9;VDB=0.993024;SGB=-0.662043;MQSB=0.974597;MQ0F=0;AC=1;AN=1;DP4=0,0,4,5;MQ=60
CP000819.1      1612    .       A       G       225     .       DP=13;VDB=0.52194;SGB=-0.676189;MQSB=0.950952;MQ0F=0;AC=1;AN=1;DP4=0,0,6,5;MQ=60
CP000819.1      9092    .       A       G       225     .       DP=14;VDB=0.717543;SGB=-0.670168;MQSB=0.916482;MQ0F=0;AC=1;AN=1;DP4=0,0,7,3;MQ=60
CP000819.1      9972    .       T       G       214     .       DP=10;VDB=0.022095;SGB=-0.670168;MQSB=1;MQ0F=0;AC=1;AN=1;DP4=0,0,2,8;MQ=60      GT:PL
CP000819.1      10563   .       G       A       225     .       DP=11;VDB=0.958658;SGB=-0.670168;MQSB=0.952347;MQ0F=0;AC=1;AN=1;DP4=0,0,5,5;MQ=60
CP000819.1      22257   .       C       T       127     .       DP=5;VDB=0.0765947;SGB=-0.590765;MQSB=1;MQ0F=0;AC=1;AN=1;DP4=0,0,2,3;MQ=60      GT:PL
CP000819.1      38971   .       A       G       225     .       DP=14;VDB=0.872139;SGB=-0.680642;MQSB=1;MQ0F=0;AC=1;AN=1;DP4=0,0,4,8;MQ=60      GT:PL
CP000819.1      42306   .       A       G       225     .       DP=15;VDB=0.969686;SGB=-0.686358;MQSB=1;MQ0F=0;AC=1;AN=1;DP4=0,0,5,9;MQ=60      GT:PL
CP000819.1      45277   .       A       G       225     .       DP=15;VDB=0.470998;SGB=-0.680642;MQSB=0.95494;MQ0F=0;AC=1;AN=1;DP4=0,0,7,5;MQ=60
CP000819.1      56613   .       C       G       183     .       DP=12;VDB=0.879703;SGB=-0.676189;MQSB=1;MQ0F=0;AC=1;AN=1;DP4=0,0,8,3;MQ=60      GT:PL
CP000819.1      62118   .       A       G       225     .       DP=19;VDB=0.414981;SGB=-0.691153;MQSB=0.906029;MQ0F=0;AC=1;AN=1;DP4=0,0,8,10;MQ=59
CP000819.1      64042   .       G       A       225     .       DP=18;VDB=0.451328;SGB=-0.689466;MQSB=1;MQ0F=0;AC=1;AN=1;DP4=0,0,7,9;MQ=60      GT:PL

This is a lot of information, so let’s take some time to make sure we understand our output.

The first few columns represent the information we have about a predicted variation.

column info
CHROM contig location where the variation occurs
POS position within the contig where the variation occurs
ID a . until we add annotation information
REF reference genotype (forward strand)
ALT sample genotype (forward strand)
QUAL Phred-scaled probability that the observed variant exists at this site (higher is better)
FILTER a . if no quality filters have been applied, PASS if a filter is passed, or the name of the filters this variant failed

In an ideal world, the information in the QUAL column would be all we needed to filter out bad variant calls. However, in reality we need to filter on multiple other metrics.

The last two columns contain the genotypes and can be tricky to decode.

column info
FORMAT lists in order the metrics presented in the final column
results lists the values associated with those metrics in order

For our file, the metrics presented are GT:PL:GQ.

metric definition
GT the genotype of this sample which for a diploid genome is encoded with a 0 for the REF allele, 1 for the first ALT allele, 2 for the second and so on. So 0/0 means homozygous reference, 0/1 is heterozygous, and 1/1 is homozygous for the alternate allele. For a diploid organism, the GT field indicates the two alleles carried by the sample, encoded by a 0 for the REF allele, 1 for the first ALT allele, 2 for the second ALT allele, etc.
PL the likelihoods of the given genotypes
GQ the Phred-scaled confidence for the genotype
AD, DP the depth per allele by sample and coverage

The Broad Institute’s VCF guide is an excellent place to learn more about the VCF file format.

Exercise

Use the grep and wc commands you’ve learned to assess how many variants are in the vcf file. Share your answer on the Padlet.

Solution

$ grep -v "#" SRR2584866_final_variants.vcf | wc -l
766

There are 766 variants in this file.

Assess the alignment (visualization) - optional step

It is often instructive to look at your data in a genome browser. Visualization will allow you to get a “feel” for the data, as well as detecting abnormalities and problems. Also, exploring the data in such a way may give you ideas for further analyses. As such, visualization tools are useful for exploratory analysis. In this lesson we will describe two different tools for visualization: a light-weight command-line based one and the Broad Institute’s Integrative Genomics Viewer (IGV) which requires software installation and transfer of files.

In order for us to visualize the alignment files, we will need to index the BAM file using samtools:

$ samtools index SRR2584866.aligned.sorted.bam

Viewing with tview

Samtools implements a very simple text alignment viewer based on the GNU ncurses library, called tview. This alignment viewer works with short indels and shows MAQ consensus. It uses different colors to display mapping quality or base quality, subjected to users’ choice. Samtools viewer is known to work with a 130 GB alignment swiftly. Due to its text interface, displaying alignments over network is also very fast.

In order to visualize our mapped reads, we use tview, giving it the sorted bam file and the reference file:

$ samtools tview SRR2584866.aligned.sorted.bam ../data/ecoli_rel606.fasta
1         11        21        31        41        51        61        71        81        91        101       111       121
AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGCTTCTGAACTGGTTACCTGCCGTGAGTAAATTAAAATTTTATTGACTTAGGTCACTAAATAC
..................................................................................................................................
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, ..................N................. ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,........................
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, ..................N................. ,,,,,,,,,,,,,,,,,,,,,,,,,,,.............................
...................................,g,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ....................................   ................
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,....................................   ....................................      ,,,,,,,,,,
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ....................................  ,,a,,,,,,,,,,,,,,,,,,,,,,,,,,,,,     .......
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, .............................  ,,,,,,,,,,,,,,,,,g,,,,,    ,,,,,,,,,,,,,,,,,,,,,,,,,,,,
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ...........................T.......   ,,,,,,,,,,,,,,,,,,,,,,,c,          ......
......................... ................................   ,g,,,,,,,,,,,,,,,,,,,      ...........................
,,,,,,,,,,,,,,,,,,,,, ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, ,,,,,,,,,,,,,,,,,,,,,,,,,,,       ..........................
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,   ................................T..  ..............................   ,,,,,,
...........................       ,,,,,,g,,,,,,,,,,,,,,,,,   ....................................         ,,,,,,
,,,,,,,,,,,,,,,,,,,,,,,,,, ....................................  ...................................        ....
....................................  ........................  ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,      ....
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,   ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
........................            .................................. .............................     ....
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,   ....................................        ..........................
...............................       ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, ....................................
...................................  ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ..................................
.................................... ,,,,,,,,,,,,,,,,,,a,,,,,,,,,,,,,,,,,        ,,,,,,,,,,,,,,,,,,,,,,,,,
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  ............................ ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

The first line of output shows the genome coordinates in our reference genome. The second line shows the reference genome sequence. The third line shows the consensus sequence determined from the sequence reads. A . indicates a match to the reference sequence, so we can see that the consensus from our sample matches the reference in most locations. That is good! If that wasn’t the case, we should probably reconsider our choice of reference.

Below the horizontal line, we can see all of the reads in our sample aligned with the reference genome. Only positions where the called base differs from the reference are shown. You can use the arrow keys on your keyboard to scroll or type ? for a help menu. To navigate to a specific position, type g. A dialogue box will appear. In this box, type the name of the “chromosome” followed by a colon and the position of the variant you would like to view (e.g. for this sample, type CP000819.1:50 to view the 50th base. Type Ctrl^C or q to exit tview.

Exercise

Visualize the alignment of the reads for our SRR2584866 sample. What variant is present at position 4377265? What is the canonical nucleotide in that position?

Share your answers on the Padlet.

Solution

$ samtools tview ~/cs_course/SRR2584866.aligned.sorted.bam ~/cs_course/data/ecoli_rel606.fasta

Then type g. In the dialogue box, type CP000819.1:4377265. G is the variant. A is canonical. This variant possibly changes the phenotype of this sample to hypermutable. It occurs in the gene mutL, which controls DNA mismatch repair.

Now that we’ve run through our workflow for a single sample, we want to repeat this workflow for our other five samples. However, we don’t want to type each of these individual steps again five more times. That would be very time consuming and error-prone, and would become impossible as we gathered more and more samples. Luckily, we already know the tools we need to use to automate this workflow and run it on as many files as we want using a single line of code. Those tools are: wildcards, for loops, and bash scripts. We’ll use all three in the next lesson.

Installing Software

It’s worth noting that all of the software we are using for this workshop has been pre-installed on our remote computer. This saves us a lot of time - installing software can be a time-consuming and frustrating task - however, this does mean that you won’t be able to walk out the door and start doing these analyses on your own computer. You’ll need to install the software first. Look at the setup instructions for more information on installing these software packages.

BWA Alignment options

BWA consists of three algorithms: BWA-backtrack, BWA-SW and BWA-MEM. The first algorithm is designed for Illumina sequence reads up to 100bp, while the other two are for sequences ranging from 70bp to 1Mbp. BWA-MEM and BWA-SW share similar features such as long-read support and split alignment, but BWA-MEM, which is the latest, is generally recommended for high-quality queries as it is faster and more accurate.

Key Points

  • Bioinformatic command line tools are collections of commands that can be used to carry out bioinformatic analyses.

  • To use most powerful bioinformatic tools, you’ll need to use the command line.

  • There are many different file formats for storing genomics data. It’s important to understand what type of information is contained in each file, and how it was derived.